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Proving that recursively enumerable languages are closed against taking prefixes

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Problem Detail: 

Define $\mathrm{Prefix} (L) = \{x\mid \exists y .xy \in L \}$. I'd love your help with proving that $\mathsf{RE}$ languages are closed under $\mathrm{Prefix}$.

I know that recursively enumerable languages are formal languages for which there exists a Turing machine that will halt and accept when presented with any string in the language as input, but may either halt and reject or loop forever when presented with a string not in the language.

Any help for how should I approach to this kind of a proof?

Asked By : Jozef

Answered By : David Lewis

Below is a hint for working with the Turing Machine (TM) formalism for RE languages. But finishing that approach from the hint depends on how you've been working with TMs.

You have a TM, say $T_L$ to accept L and you want to construct a new TM $T_L^'$ for $\text{Prefix}(L)$. You can start $T_L^'$ on a string $x$ and then do something to finish up with the hypothetical $y$ that completes $xy\in L$. How you do that depends somewhat on the methods you have been using to work with TMs. But that's a hint so far.

Best Answer from StackOverflow

Question Source : http://cs.stackexchange.com/questions/1731

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