I don't understand why $n \log \log n $ is not $\Theta (n)$.
Suppose we give $n$ a value of $10,000$. Then $n \log \log n$ is $6020.6$. So isn't $n \log \log n$ upper- and lower-bounded by $n$, as $n \log \log n \geq Cn$?
Asked By : Malcolm X
Answered By : Yuval Filmus
As $n$ grows bigger, the ratio between $n\log\log n$ and $n$, namely $\log\log n$, tends to infinity. Hence it is not possible to upper bound $n\log\log n \leq Cn$ for any constant $C$. If you stare at this inequality, you discover that the constant $C$ must satisfy $\log\log n \leq C$ for all $n$, yet the function $\log\log n$ is not bounded.
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Question Source : http://cs.stackexchange.com/questions/10281
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